計(jì)算時(shí)間差 **/
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String systemTime = sdf .format(new Date()).toString();
將截取到的時(shí)間字符串轉(zhuǎn)化為時(shí)間格式的字符串 **/
Date begin=sdf.parse(2008-03-28 11:55:30);
Date end = sdf.parse(systemTime);
long between=(end.getTime()-begin.getTime())/1000;//除以1000是為了轉(zhuǎn)換成秒
long day=between/(24*3600);
long hour=between%(24*3600)/3600;
long minute=between%3600/60;
long second=between%60/60;
if((hour==0)&&(day==0)&&(minute<=30)) { /****/}
比如:現(xiàn)在是2004-03-26 13:31:40
過去是:2004-01-02 11:30:24
我現(xiàn)在要獲得兩個(gè)日期差,差的形式為:XX天XX小時(shí)XX分XX秒
方法一:
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try
{
Date d1 = df.parse("2004-03-26 13:31:40");
Date d2 = df.parse("2004-01-02 11:30:24");
long diff = d1.getTime() - d2.getTime();
long days = diff / (1000 * 60 * 60 * 24);
}
catch (Exception e)
{
}
方法二:
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date now = df.parse("2004-03-26 13:31:40");
java.util.Date date=df.parse("2004-01-02 11:30:24");
long l=now.getTime()-date.getTime();
long day=l/(24*60*60*1000);
long hour=(l/(60*60*1000)-day*24);
long min=((l/(60*1000))-day*24*60-hour*60);
long s=(l/1000-day*24*60*60-hour*60*60-min*60);
System.out.println(""+day+"天"+hour+"小時(shí)"+min+"分"+s+"秒");
方法三:
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date begin=dfs.parse("2004-01-02 11:30:24");
java.util.Date end = dfs.parse("2004-03-26 13:31:40");
long between=(end.getTime()-begin.getTime())/1000;//除以1000是為了轉(zhuǎn)換成秒
long day1=between/(24*3600);
long hour1=between%(24*3600)/3600;
long minute1=between%3600/60;
long second1=between%60/60;
System.out.println(""+day1+"天"+hour1+"小時(shí)"+minute1+"分"+second1+"秒");
我在這里出個(gè)錯(cuò)誤,天數(shù)不對(duì),仔細(xì)檢查發(fā)現(xiàn)是時(shí)間的格式問題
這里dateA,dateB的格式要與yyyy-MM-dd一致!切記!
/**
* 根據(jù)兩個(gè)日期,取得相隔的天數(shù)
* 方法名 :
* @param dateA
* @param dateB
* @return
*/
public static int getBetweenDayNumber(String dateA, String dateB) {
long dayNumber = 0;
long DAY = 24L * 60L * 60L * 1000L;
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd");
try {
java.util.Date d1 = df.parse(dateA);
java.util.Date d2 = df.parse(dateB);
dayNumber = (d2.getTime() - d1.getTime()) / DAY;
} catch (Exception e) {
e.printStackTrace();
}
return (int) dayNumber;
}
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