經(jīng)典c程序100例==91--100【程序91】題目：時間函數(shù)舉例11.程序分析：2.程序源代碼：#include "stdio.h"#include "time.h"void main(){ time_t lt; /*define a longint time varible*/lt=time(NULL);/*system time and date*/printf(ctime(<)); /*english format output*/printf(asctime(localtime(<)));/*tranfer to tm*/printf(asctime(gmtime(<))); /*tranfer to Greenwich time*/}==============================================================【程序92】題目：時間函數(shù)舉例21.程序分析： 2.程序源代碼：/*calculate time*/#include "time.h"#include "stdio.h"main(){ time_t start,end;int i;start=time(NULL);for(i=0;i<3000;i++){ printf("\1\1\1\1\1\1\1\1\1\1\n");}end=time(NULL);printf("\1: The different is %6.3f\n",difftime(end,start));}==============================================================【程序93】題目：時間函數(shù)舉例31.程序分析：2.程序源代碼：/*calculate time*/#include "time.h"#include "stdio.h"main(){ clock_t start,end;int i;double var;start=clock();for(i=0;i<10000;i++){ printf("\1\1\1\1\1\1\1\1\1\1\n");}end=clock();printf("\1: The different is %6.3f\n",(double)(end-start));}==============================================================【程序94】題目：時間函數(shù)舉例4,一個猜數(shù)游戲，判斷一個人反應快慢。（版主初學時編的）1.程序分析：2.程序源代碼：#include "time.h"#include "stdlib.h"#include "stdio.h"main(){char c;clock_t start,end;time_t a,b;double var;int i,guess;srand(time(NULL));printf("do you want to play it.(‘y‘ or ‘n‘) \n");loop:while((c=getchar())==‘y‘){i=rand()%100;printf("\nplease input number you guess:\n");start=clock();a=time(NULL);scanf("%d",&guess);while(guess!=i){if(guess>i){printf("please input a little smaller.\n");scanf("%d",&guess);}else{printf("please input a little bigger.\n");scanf("%d",&guess);}}end=clock();b=time(NULL);printf("\1: It took you %6.3f seconds\n",var=(double)(end-start)/18.2);printf("\1: it took you %6.3f seconds\n\n",difftime(b,a));if(var<15)printf("\1\1 You are very clever! \1\1\n\n");else if(var<25)printf("\1\1 you are normal! \1\1\n\n");elseprintf("\1\1 you are stupid! \1\1\n\n");printf("\1\1 Congradulations \1\1\n\n");printf("The number you guess is %d",i);}printf("\ndo you want to try it again?(\"yy\".or.\"n\")\n");if((c=getch())==‘y‘)goto loop;}==============================================================【程序95】題目：家庭財務(wù)管理小程序1.程序分析：2.程序源代碼：/*money management system*/#include "stdio.h"#include "dos.h"main(){FILE *fp;struct date d;float sum,chm=0.0;int len,i,j=0;int c;char ch[4]="",ch1[16]="",chtime[12]="",chshop[16],chmoney[8];pp: clrscr();sum=0.0;gotoxy(1,1);printf("|---------------------------------------------------------------------------|");gotoxy(1,2);printf("| money management system(C1.0) 2000.03 |");gotoxy(1,3);printf("|---------------------------------------------------------------------------|");gotoxy(1,4);printf("| -- money records -- | -- today cost list -- |");gotoxy(1,5);printf("| ------------------------ |-------------------------------------|");gotoxy(1,6);printf("| date: -------------- | |");gotoxy(1,7);printf("| | | | |");gotoxy(1,8);printf("| -------------- | |");gotoxy(1,9);printf("| thgs: ------------------ | |");gotoxy(1,10);printf("| | | | |");gotoxy(1,11);printf("| ------------------ | |");gotoxy(1,12);printf("| cost: ---------- | |");gotoxy(1,13);printf("| | | | |");gotoxy(1,14);printf("| ---------- | |");gotoxy(1,15);printf("| | |");gotoxy(1,16);printf("| | |");gotoxy(1,17);printf("| | |");gotoxy(1,18);printf("| | |");gotoxy(1,19);printf("| | |");gotoxy(1,20);printf("| | |");gotoxy(1,21);printf("| | |");gotoxy(1,22);printf("| | |");gotoxy(1,23);printf("|---------------------------------------------------------------------------|");i=0;getdate(&d);sprintf(chtime,"%4d.%02d.%02d",d.da_year,d.da_mon,d.da_day);for(;;){gotoxy(3,24);printf(" Tab __browse cost list Esc __quit");gotoxy(13,10);printf(" ");gotoxy(13,13);printf(" ");gotoxy(13,7);printf("%s",chtime);j=18;ch[0]=getch();if(ch[0]==27)break;strcpy(chshop,"");strcpy(chmoney,"");if(ch[0]==9){mm:i=0;fp=fopen("home.dat","r+");gotoxy(3,24);printf(" ");gotoxy(6,4);printf(" list records ");gotoxy(1,5);printf("|-------------------------------------|");gotoxy(41,4);printf(" ");gotoxy(41,5);printf(" |");while(fscanf(fp,"%10s%14s%f\n",chtime,chshop,&chm)!=EOF){ if(i==36){ getch();i=0;}if ((i%36)<17){ gotoxy(4,6+i);printf(" ");gotoxy(4,6+i);}elseif((i%36)>16){ gotoxy(41,4+i-17);printf(" ");gotoxy(42,4+i-17);}i++;sum=sum+chm;printf("%10s %-14s %6.1f\n",chtime,chshop,chm);}gotoxy(1,23);printf("|---------------------------------------------------------------------------|");gotoxy(1,24);printf("| |");gotoxy(1,25);printf("|---------------------------------------------------------------------------|");gotoxy(10,24);printf("total is %8.1f$",sum);fclose(fp);gotoxy(49,24);printf("press any key to.....");getch();goto pp;}else{while(ch[0]!=‘\r‘){ if(j<10){ strncat(chtime,ch,1);j++;}if(ch[0]==8){len=strlen(chtime)-1;if(j>15){ len=len+1; j=11;}strcpy(ch1,"");j=j-2;strncat(ch1,chtime,len);strcpy(chtime,"");strncat(chtime,ch1,len-1);gotoxy(13,7);printf(" ");}gotoxy(13,7);printf("%s",chtime);ch[0]=getch();if(ch[0]==9)goto mm;if(ch[0]==27)exit(1);}gotoxy(3,24);printf(" ");gotoxy(13,10);j=0;ch[0]=getch();while(ch[0]!=‘\r‘){ if (j<14){ strncat(chshop,ch,1);j++;}if(ch[0]==8){ len=strlen(chshop)-1;strcpy(ch1,"");j=j-2;strncat(ch1,chshop,len);strcpy(chshop,"");strncat(chshop,ch1,len-1);gotoxy(13,10);printf(" ");}gotoxy(13,10);printf("%s",chshop);ch[0]=getch();}gotoxy(13,13);j=0;ch[0]=getch();while(ch[0]!=‘\r‘){ if (j<6){ strncat(chmoney,ch,1);j++;}if(ch[0]==8){ len=strlen(chmoney)-1;strcpy(ch1,"");j=j-2;strncat(ch1,chmoney,len);strcpy(chmoney,"");strncat(chmoney,ch1,len-1);gotoxy(13,13);printf(" ");}gotoxy(13,13);printf("%s",chmoney);ch[0]=getch();}if((strlen(chshop)==0)||(strlen(chmoney)==0))continue;if((fp=fopen("home.dat","a+"))!=NULL);fprintf(fp,"%10s%14s%6s",chtime,chshop,chmoney);fputc(‘\n‘,fp);fclose(fp);i++;gotoxy(41,5+i);printf("%10s %-14s %-6s",chtime,chshop,chmoney);}}}==============================================================【程序96】題目：計算字符串中子串出現(xiàn)的次數(shù)1.程序分析：2.程序源代碼：#include "string.h"#include "stdio.h"main(){ char str1[20],str2[20],*p1,*p2;int sum=0;printf("please input two strings\n");scanf("%s%s",str1,str2);p1=str1;p2=str2;while(*p1!=‘\0‘){if(*p1==*p2){while(*p1==*p2&&*p2!=‘\0‘){p1++;p2++;}}elsep1++;if(*p2==‘\0‘)sum++;p2=str2;}printf("%d",sum);getch();}==============================================================【程序97】題目：從鍵盤輸入一些字符，逐個把它們送到磁盤上去，直到輸入一個#為止。1.程序分析： 2.程序源代碼：#include "stdio.h"main(){ FILE *fp;char ch,filename[10];scanf("%s",filename);if((fp=fopen(filename,"w"))==NULL){printf("cannot open file\n");exit(0);}ch=getchar();ch=getchar();while(ch!=‘#‘){fputc(ch,fp);putchar(ch);ch=getchar();}fclose(fp);}==============================================================【程序98】題目：從鍵盤輸入一個字符串，將小寫字母全部轉(zhuǎn)換成大寫字母，然后輸出到一個磁盤文件“test”中保存?！ ≥斎氲淖址?！結(jié)束。1.程序分析：2.程序源代碼：#include "stdio.h"main(){FILE *fp;char str[100],filename[10];int i=0;if((fp=fopen("test","w"))==NULL){ printf("cannot open the file\n");exit(0);}printf("please input a string:\n");gets(str);while(str[i]!=‘!‘){ if(str[i]>=‘a(chǎn)‘&&str[i]<=‘z‘)str[i]=str[i]-32;fputc(str[i],fp);i++;}fclose(fp);fp=fopen("test","r");fgets(str,strlen(str)+1,fp);printf("%s\n",str);fclose(fp);}==============================================================【程序99】題目：有兩個磁盤文件A和B,各存放一行字母，要求把這兩個文件中的信息合并（按字母順序排列）， 輸出到一個新文件C中。1.程序分析：2.程序源代碼：#include "stdio.h"main(){ FILE *fp;int i,j,n,ni;char c[160],t,ch;if((fp=fopen("A","r"))==NULL){printf("file A cannot be opened\n");exit(0);}printf("\n A contents are :\n");for(i=0;(ch=fgetc(fp))!=EOF;i++){c[i]=ch;putchar(c[i]);}fclose(fp);ni=i;if((fp=fopen("B","r"))==NULL){printf("file B cannot be opened\n");exit(0);}printf("\n B contents are :\n");for(i=0;(ch=fgetc(fp))!=EOF;i++){c[i]=ch;putchar(c[i]);}fclose(fp);n=i;for(i=0;i<n;i++)for(j=i+1;j<n;j++)if(c[i]>c[j]){t=c[i];c[i]=c[j];c[j]=t;}printf("\n C file is:\n");fp=fopen("C","w");for(i=0;i<n;i++){ putc(c[i],fp);putchar(c[i]);}fclose(fp);}==============================================================【程序100】題目：有五個學生，每個學生有3門課的成績，從鍵盤輸入以上數(shù)據(jù)（包括學生號，姓名，三門課成績），計算出 平均成績，況原有的數(shù)據(jù)和計算出的平均分數(shù)存放在磁盤文件"stud"中。1.程序分析：2.程序源代碼：#include "stdio.h"struct student{ char num[6];char name[8];int score[3];float avr;} stu[5];main(){int i,j,sum;FILE *fp;/*input*/for(i=0;i<5;i++){ printf("\n please input No. %d score:\n",i);printf("stuNo:");scanf("%s",stu[i].num);printf("name:");scanf("%s",stu[i].name);sum=0;for(j=0;j<3;j++){ printf("score %d.",j+1);scanf("%d",&stu[i].score[j]);sum+=stu[i].score[j];}stu[i].avr=sum/3.0;}fp=fopen("stud","w");for(i=0;i<5;i++)if(fwrite(&stu[i],sizeof(struct student),1,fp)!=1)printf("file write error\n");fclose(fp);}
