上次提出了一個(gè)ajax下載中文編碼問(wèn)題，這次有遇到了ajax的上傳中文亂麻問(wèn)題
繼續(xù)bs各種編碼：）
遇到問(wèn)題：在使用xhr發(fā)出請(qǐng)求時(shí)，請(qǐng)求的url中參數(shù)帶中文，這時(shí)在后臺(tái)解析request得不到中文
如：
request = new ActiveXObject("Microsoft.XMLHTTP");
request.open("GET", url);中我的url需要帶中文參數(shù)
直接加參數(shù)是在后臺(tái)解析不出來(lái)的，所以我使用方法對(duì)url進(jìn)行編碼轉(zhuǎn)換
request = new ActiveXObject("Microsoft.XMLHTTP");
request.open("GET", uriFunc());
//省略了對(duì)象定義
//..
function uriFunc() {
var separator = "?";
if (uri.indexOf("?") >= 0)
separator = "&";
return uri + separator + paramName + "=" + escape(inputField.value,‘utf-8‘);
}
然后就要在后臺(tái)進(jìn)行解碼了
以為沒法直接從request中取到編碼字符串，所以使用方法先取出url，然后再取出url的參數(shù)進(jìn)行解碼
取出url，以及取參數(shù)方法
String exfirstword = getUrlParameter(unescape(request.getQueryString()),"excludeuser");
public String getUrlParameter(String str,String targetstr){
String[] stringarray = str.split("&") ;
for(int i=0;i<stringarray.length;i++){
if(stringarray[i].startsWith(targetstr)){
stringarray=stringarray[i].split("=");
break;
}
}
return stringarray[1];
}
//解碼方法
//以下是對(duì)js的escape進(jìn)行解碼
private final static byte[] val = { 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x00, 0x01,
0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08, 0x09, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x0A, 0x0B, 0x0C, 0x0D, 0x0E, 0x0F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x0A, 0x0B, 0x0C, 0x0D, 0x0E, 0x0F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F,
0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F, 0x3F };
/**
* 解碼 說(shuō)明：本方法保證 不論參數(shù)s是否經(jīng)過(guò)escape()編碼，均能得到正確的“解碼”結(jié)果
*
* @param s
* @return
*/
public static String unescape(String s) {
StringBuffer sbuf = new StringBuffer();
int i = 0;
int len = s.length();
while (i < len) {
int ch = s.charAt(i);
if (‘A‘ <= ch && ch <= ‘Z‘) { // ‘A‘..‘Z‘ : as it was
sbuf.append((char) ch);
} else if (‘a‘ <= ch && ch <= ‘z‘) { // ‘a(chǎn)‘..‘z‘ : as it was
sbuf.append((char) ch);
} else if (‘0‘ <= ch && ch <= ‘9‘) { // ‘0‘..‘9‘ : as it was
sbuf.append((char) ch);
} else if (ch == ‘-‘ || ch == ‘_‘ // unreserved : as it was
|| ch == ‘.‘ || ch == ‘!‘ || ch == ‘~‘ || ch == ‘*‘
|| ch == ‘\‘‘ || ch == ‘(‘ || ch == ‘)‘) {
sbuf.append((char) ch);
} else if (ch == ‘%‘) {
int cint = 0;
if (‘u‘ != s.charAt(i + 1)) { // %XX : map to ascii(XX)
cint = (cint << 4) | val[s.charAt(i + 1)];
cint = (cint << 4) | val[s.charAt(i + 2)];
i += 2;
} else { // %uXXXX : map to unicode(XXXX)
cint = (cint << 4) | val[s.charAt(i + 2)];
cint = (cint << 4) | val[s.charAt(i + 3)];
cint = (cint << 4) | val[s.charAt(i + 4)];
cint = (cint << 4) | val[s.charAt(i + 5)];
i += 5;
}
sbuf.append((char) cint);
} else { // 對(duì)應(yīng)的字符未經(jīng)過(guò)編碼
sbuf.append((char) ch);
}
i++;
}
return sbuf.toString();
}
這時(shí)候得到的
exfirstword 就是正確的中文了
問(wèn)題解決
