fdisk is started by typing (as root)fdiskdevice at the command prompt.device might be something like /dev/hda or /dev/sda (see Section 2.1.1). The basicfdisk commands you need are:

pprint the partition table

ncreate a new partition

ddelete a partition

qquit without saving changes

wwrite the new partition table and exit

 

Changes you make to the partition table do not take effect until you issue the write (w) command.Here is a sample partition table:

Disk /dev/hdb: 64 heads, 63 sectors, 621 cylinders Units = cylinders of 4032 * 512 bytes Device Boot Start End Blocks Id System /dev/hdb1 * 1 184 370912+ 83 Linux /dev/hdb2 185 368 370944 83 Linux /dev/hdb3 369 552 370944 83 Linux /dev/hdb4 553 621 139104 82 Linux swap

The first line shows the geometry of your hard drive. It may not bephysically accurate, but you can accept it as though it were. The harddrive in this example is made of 32 double-sided platters with onehead on each side (probably not true). Each platter has 621 concentrictracks. A 3-dimensional track (the same track on all disks) is calleda cylinder. Each track is divided into 63 sectors. Each sectorcontains 512 bytes of data. Therefore the block size in the partitiontable is 64 heads * 63 sectors * 512 bytes er...divided by 1024. (See4 for discussion onproblems with this calculation.) The start and end values are cylinders.

The overview:

Decide on the size of your swap space (see Section 4.4) and where it ought to go (see Section 4.4.3).Divide up the remaining space for the three other partitions.

Example:

I start fdisk from the shell prompt:

# fdisk /dev/hdb

which indicates that I am using the second drive on my IDE controller.(See Section 2.1.) When I print the (empty) partition table,I just get configuration information.

Command (m for help): p Disk /dev/hdb: 64 heads, 63 sectors, 621 cylinders Units = cylinders of 4032 * 512 bytes

I knew that I had a 1.2Gb drive, but now I really know: 64 * 63 * 512* 621 = 1281982464 bytes. I decide to reserve 128Mb of that space forswap, leaving 1153982464. If I use one of my primary partitions forswap, that means I have three left for ext2 partitions. Dividedequally, that makes for 384Mb per partition. Now I get to work.

Command (m for help): n Command action e extended p primary partition (1-4) p Partition number (1-4): 1 First cylinder (1-621, default 1):<RETURN> Using default value 1 Last cylinder or +size or +sizeM or +sizeK (1-621, default 621): +384M

Next, I set up the partition I want to use for swap:

Command (m for help): n Command action e extended p primary partition (1-4) p Partition number (1-4): 2 First cylinder (197-621, default 197):<RETURN> Using default value 197 Last cylinder or +size or +sizeM or +sizeK (197-621, default 621): +128M

Now the partition table looks like this:

Device Boot Start End Blocks Id System /dev/hdb1 1 196 395104 83 Linux /dev/hdb2 197 262 133056 83 Linux

I set up the remaining two partitions the same way I did the first.Finally, I make the first partition bootable:

Command (m for help): a Partition number (1-4): 1

And I make the second partition of type swap:

Command (m for help): t Partition number (1-4): 2 Hex code (type L to list codes): 82 Changed system type of partition 2 to 82 (Linux swap) Command (m for help): p

The end result:

Disk /dev/hdb: 64 heads, 63 sectors, 621 cylinders Units = cylinders of 4032 * 512 bytes Device Boot Start End Blocks Id System /dev/hdb1 * 1 196 395104+ 83 Linux /dev/hdb2 197 262 133056 82 Linux swap /dev/hdb3 263 458 395136 83 Linux /dev/hdb4 459 621 328608 83 Linux

Finally, I issue the write command (w) to write the table on the disk.

Side topics:

 

• Section 10.2

• Section 10.1

• Section 10.3

 

5.3. Mixed primary and logical partitions

The overview: create one use one of the primarypartitions to house all the extra partitions. Then create logicalpartitions within it. Create the other primary partitions before orafter creating the logical partitions.

Example:

I start fdisk from the shell prompt:

# fdisk /dev/sda            

First I figure out how many partitions I want. I know my drive has a183Gb capacity and I want 26Gb partitions (because I happen to haveback-up tapes that are about that size).

183Gb / 26Gb = ~7

so I will need 7 partitions. Even though fdisk accepts partition sizesexpressed in Mb and Kb, I decide to calculate the number of cylindersthat will end up in each partition because fdisk reports start andstop points in cylinders. I see when I enter fdisk that I have 22800cylinders.

> The number of cylinders for this disk is set to 22800.  There is            > nothing wrong with that, but this is larger than 1024, and could in            > certain setups cause problems with: 1) software that runs at boot            > time (e.g., LILO) 2) booting and partitioning software from other            > OSs  (e.g., DOS FDISK, OS/2 FDISK)            

Since I have 4 primary partitions, 3 of them can be 3258long. The extended partition will have to be (4 * 3258), or 13032,cylinders long in order to contain the 4 logical partitions.

I enter the following commands to set up the first of the 3 primarypartitions (stuff I type is bold ):

            Command (m for help): n            Command action            e   extended            p   primary partition (1-4)            p            Partition number (1-4): 1            First cylinder (1-22800, default 1): <RETURN>            Using default value 1            Last cylinder or +size or +sizeM or +sizeK (1-22800, default 22800): 3258            

Partition number (1-4): 4            First cylinder (9775-22800, default 9775): <RETURN>            Using default value 9775            Last cylinder or +size or +sizeM or +sizeK (9775-22800, default 22800): <RETURN>            Using default value 22800            

/dev/sda1             1      3258  26169853+  83  Linux            /dev/sda2          3259      6516  26169885   83  Linux            /dev/sda3          6517      9774  26169885   83  Linux            /dev/sda4          9775     22800 104631345    5  Extended            

Command (m for help):  n            First cylinder (9775-22800, default 9775): <RETURN>            Using default value 9775            Last cylinder or +size or +sizeM or +sizeK (9775-22800, default 22800): 13032            

   Device Boot    Start       End    Blocks   Id  System            /dev/sda1             1      3258  26169853+  83  Linux            /dev/sda2          3259      6516  26169885   83  Linux            /dev/sda3          6517      9774  26169885   83  Linux            /dev/sda4          9775     22800 104631345    5  Extended            /dev/sda5          9775     13032  26169853+  83  Linux            /dev/sda6         13033     16290  26169853+  83  Linux            /dev/sda7         16291     19584  26459023+  83  Linux            /dev/sda8         19585     22800  25832488+  83  Linux            

5.4. Submitted Examples

I'd like to submit my partition layout, because it works well withany distribution of Linux (even big RPM based ones).I have one hard drive that ... is 10 gigs, exactly. Windowscan't see above 9.3 gigs of it, but Linux can see it all, and use itall. It also has much more than 1024 cylenders.

I also noticed that you don't have any REAL examples of partitiontables, and for newbies I HIGHLY suggest putting quite a few up. I'mfreshly out of the newbie stage, and partitioning was what messed me upthe most.

Valkor